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Are you getting a “TypeError: ‘type’ object is not subscriptable” error in Python?
Let’s say that you just’re getting an error from this code, “emptylist += str[strlength – 1]”.
In that case, the error is attributable to this a part of the code, “str[strlength – 1]”.
On this information, you’ll discover ways to repair “TypeError: ‘type’ object is not subscriptable” in Python, Pandas, or in a loop.
The best way to Repair “TypeError: ‘type’ object is not subscriptable”
Earlier than (improper):
name1 = "tom" # Index values of [0,1,2]
emptylist =[]
strlength = len(name1) # Returns size of three
whereas strlength > 0:
emptylist += str[strlength - 1] #Final index worth of the variable "name1"
strlength = strlength - 1
print(emptylist)
Repair: The “str” in “str[strlength – 1]” must be changed with the variable identify at first (“name1”).
Substitute “str” with “name1”.
After (appropriate):
name1 = "tom" # Index values of [0,1,2]
emptylist =[]
strlength = len(name1) # Returns size of three
whereas strlength > 0:
emptylist += name1[strlength - 1] #Final index worth of the variable "name1"
strlength = strlength - 1
print(emptylist)
On this situation, the “str” in “str[strlength – 1]” code is improper.
The code has a variable referred to as “name1” and “Tom”.
Do notice that the size of the string could also be 3, however that goes from 1 to three.
It doesn’t equate to the index but it surely simply creates the size.
Within the code, you’re saying that whereas the string size is larger than 0, do the following two traces.
The “+=” is principally when every time it’s iterating, it’s simply including the variable that it finds into the listing.
And the following factor is “str” which has field brackets and never the traditional brackets.
Nevertheless, it’s going again one step as a result of it’s beginning at “-1”.
The explanation for that’s you must return one step to carry it again to the index worth of two.
And because it loops by way of this then, it goes again to the index worth of 1 and goes again to the index worth of 0.
To repair this, it’s worthwhile to substitute “str” with the variable identify at first (“name1”).
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